(4x-3)(x^2-4x+3)=0

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Solution for (4x-3)(x^2-4x+3)=0 equation: 


Simplifying
(4x + -3)(x2 + -4x + 3) = 0

Reorder the terms:
(-3 + 4x)(x2 + -4x + 3) = 0

Reorder the terms:
(-3 + 4x)(3 + -4x + x2) = 0

Multiply (-3 + 4x) * (3 + -4x + x2)
(-3(3 + -4x + x2) + 4x * (3 + -4x + x2)) = 0
((3 * -3 + -4x * -3 + x2 * -3) + 4x * (3 + -4x + x2)) = 0
((-9 + 12x + -3x2) + 4x * (3 + -4x + x2)) = 0
(-9 + 12x + -3x2 + (3 * 4x + -4x * 4x + x2 * 4x)) = 0
(-9 + 12x + -3x2 + (12x + -16x2 + 4x3)) = 0

Reorder the terms:
(-9 + 12x + 12x + -3x2 + -16x2 + 4x3) = 0

Combine like terms: 12x + 12x = 24x
(-9 + 24x + -3x2 + -16x2 + 4x3) = 0

Combine like terms: -3x2 + -16x2 = -19x2
(-9 + 24x + -19x2 + 4x3) = 0

Solving
-9 + 24x + -19x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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